Expand the following: $$\begin{array}{rl}S{s}_2=\frac{50\ast (\frac{80}{3.6}{)}^2}{(\frac{80}{3.6}{)}^2\ast cos5-2\ast 50\ast 9.81\ast sin5}\ast m& =\frac{50\ast {22.22}^2}{{22.22}^2\ast 0.997-981\ast 0.087}\ast m\\ & =\frac{50\ast 493.72}{493.72\ast 0.997-85.35}\ast m\\ & =\frac{24612}{492.24-85.35}\ast m\\ & =\frac{24612}{406.89}\ast m\\ & =60.49\ast m\end{array}$$